🎮 Nvidia — Big 🐻 comes out of hibernation.● 4D
NASDAQ:NVDA
I really want to believe that only the first wave of V of (III) is formed from the top of triangle IV . But it is necessary to prepare for the worst — for the main scenario, where on the horizon the senior correction of the fourth wave of the " Supercycle " degree with approximate goals of ⁓ 10 $.
● 1D
NASDAQ:NVDA
The area indicated by the pink channel can serve as a reversal target. In the range of 830-870 , there is a cluster of significant Fibo extensions. The primary wave ⑤ will complete its target by reaching 161.8% of the wavelength ① . When the values of 830-840 are reached, the wave ④ will divide the wave V in the Fibonacci ratio, and the waves (1)-(5) in the composition ⑤ of V will reach equality.
● 2h
NASDAQ:NVDA
It is very likely that the wave (4) is completed by a contracting triangle with a further exit up. An excellent setup for buy trades with an eye on the early resumption of growth with the final wave (5) of ⑤ .
The wave marking in the double circle parenthesis corresponds to the green marking in the circle on the chart.
Ewpattern
Apple -A company that you want to invest in over and over again.●● Mine scenario
● 2W
NASDAQ:AAPL
There is no big changes from the last update . Now the wave (III) or (V) " Supercycle " is developing, as part of which 5 of (3) is extended. The approximate targets for the third waves correspond to the color of the wave degree.
● 1D
NASDAQ:AAPL
The top of wave ((iii)) was determined with high accuracy. Next, a sideways corrections was expected in the form of a triangle, which, as will be demonstrated later in alternative count, could have already been formed.
● 4h
NASDAQ:AAPL
At the moment, I expect the correction to transform into a wider contracting triangle in the form of a running model type. The targets for the wave 5 of (3) are located at the level of 214 , but later they can be revised based on the rule of the ratio of the lengths of the first and fifth waves of the impulse.
● 30m
NASDAQ:AAPL
On the lower timeframe, not everything is so clear. A series of local sideways corrections in the form of triangles forces us to adopt a variant of counting with a ending diagonal with c of (b) .
●● Alternative scenario
● 4h
NASDAQ:AAPL
An alternative count suggests considering the probability of a completed triangle ((iv)) . If we turn to the arithmetic price scale, the lower limit of the ascending channel has been reached. The first targets for wave ((v)) of 5 have also already reached ( ((v)) = ((i)) ). Further goals: 165 and 197 .
● 30m
NASDAQ:AAPL
So far, I have nothing to offer you except of the diagonal in the current count and the top of the triangle ((iv)) 112.60 in the lower degree. I plan to make any trading decisions in this situation only if the diagonal is fully formed or broken in its current form and with a powerful exit up.
The wave marking in the double circle parenthesis corresponds to the green marking in the circle on the chart.
🚀Will Bitcoin survive the fourth wave of the supercycle?🌠●● Mine scenario
● 1W
On the left is a variant of count of the SP500 index, in which the wave ((5)) of V forms a diagonal. On the right is a variant of count of BTCUSD , which assumes a sideways correction by the wave ((4)) , as part of the final wave V of (III) .
● 1D
Probably, wave (B) of ((4)) is forming a single zigzag (double), followed by a decline in wave (C) . The critical level for wave (B) of ((4)) is 36900 , if it is broken, then wave (B)> 200% of wave (A) , which is unacceptable in triangles and, most likely, in flats.
● 4h
Count of the wave structure in the 4h interval. The first targets for wave iii of (v) are located at the level of 24470 , at which point wave iii will equal 1.618 of wave i .
The wave marking in the double circle parenthesis corresponds to the green marking in the circle on the chart.